Warning: Trying to access array offset on value of type bool in /home/topgsnkq/timelyhomework.com/wp-content/themes/enfold/framework/php/function-set-avia-frontend.php on line 570

The conductivity of a saturated solution

We need to equate the total payments to the total obligations due at the end of year three. Debts The values of the R780 and R7 000 debts must be moved to the end of year three. source: helpinhomework.org For the R780 debt The future value is = P (1 + R) T S = 780 (1 + 0.11) 1 S = 865.80 For the R7 000 debt The value of the R7 000 debt at the end of year three is = P (1 + R) -T S = 7000 (1 + 0.11) -1 S = R6 306.31 Payments There are two payments, namely R1 300 at the end of year one and R x at the end of year three. For the R1 300 payment The future value is = P (1 + R) T S = 1300 (1 + 0.11) 2 S = R1 601.73Total payments = Total obligations1601.73 + x = 865.80 + 6306.611601.73 + x = 7172.11 x = 7172.11 – 1601.73x = R5 570.38

 
"Looking for a Similar Assignment? Order now and Get 10% Discount! Use Code "GET10" in your order"

If this is not the paper you were searching for, you can order your 100% plagiarism free, professional written paper now!

Order Now Just Browsing

All of our assignments are originally produced, unique, and free of plagiarism.

Free Revisions Plagiarism Free 24x7 Support